HW due next Monday
1.1 p.5 Read problems 1-14. Do even.
1.2 1(c), 2(a), 4, 11, 14, 17, 20, 22
1.1 and 1.2 Definitions
Laplace equation
partial derivatives
d2u/dx2 + d2u/dy2 = 0
heat equations
du/dt = d2u/dx2 + d2u/dy2
u = u(x,t)
Second order PDE
Existance and uniqueness theorem
general idea:
An nth order ODE needs n initial values to pick up a unique solution.
P. 12 gives more complete theorem
Show that f(x) = x2 - x-1 is a
solution to d2y/dx2
- (2/(x2))y = 0
f'(x) = 2x + x-2
f''(x) = 2 - 2(x-3)
LHS = 2 - 2x-3 - (2/(x2))(x2 - x-1)
(f(x) is substituted for y)
= 2x-1/x2
Example
y'' - 3y' + 2y = 0
Find constant m, such that y = emx is a solution.
y' = memx
y'' = (m2)emx
(m2)emx - 3memx + 2emx = 0
m2 - 3m + 2 = 0
(m - 1)(m - 2) = 0
m = 1 or m = 2
Therefore y = ex or y=e2x
should be solutions
y = ex
y' = ex
y'' = ex
y = e2x
y' = 2e2x
y'' = 4e2x
| Note: The Microsoft Windows Symbol font has been used to display (d--should be delta), (¶--should be d curving left), (ò--should be the integration sign), and (W--should be Omega). Math Symbols |